10.5x-10=36-3y=14+A,x=()y=()

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10.5x-10=36-3y=14+A,x=()y=()
若10.5x -10 = 36-3y=14+A,x=?y=?

10.5x-10=14+A10.5x=24+A21x=48+2Ax=(48+2A)/2136-3y=14+A-3y=-22+A3y=22-Ay=(22-A)/3答:x=(48+2A)/21y=(22-

(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai

(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=4x-2y-z-5x[6y-(x+y)]+x-(3y-10z)=4x-2y-z-30xy+5x²+5xy+x-3

{ x-y/7-x+y/10=1/2 {2(x-y)+5(x+y)=3

x-y/7-x+y/10=1/2两边乘7010x-10y-7x-7y=353x-17y=35(1)2(x-y)+5(x+y)=32x-2y+5x+5y=37x+3y=3(2)(2)*3-(1)*79y

用加减法解方程组:{(x+y)/6+(x-y)/10=3 (x+y)/6+(y-x)/10=-1

(x+y)/6+(x-y)/10=3①(x+y)/6+(y-x)/10=-1②①可变为:(x+y)/6-(y-x)/10=3③②+③=(x+y)/3=2得x+y=6④②-③=(y-x)/5=-4得y-

3x+3y+2x-2y=36 4x+4y-5x-5y=2

3x+3y+2x-2y=36①4x+4y-5x+5y=2②(3x+2x)+(3y-2y)=365x+y=36y=36-5x③把③带入②得,-x+9(36-5x)=2x=7把x=7带入③得y=1∴此方程

3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2 解方程组

5x+y=369y-x=2即45y-10+y=36y=1x=7

解下X+X+X+Y=52 Y+Y+Y+X=36 求X=? Y=?还要过程

就是3X+Y=523Y+X=36相加4X+4Y=88X+Y=223X+Y=52所以3X+Y-X-Y=52-222X=30X=15Y=22-X=7

已知x-y-3绝对值+(2x+2y+10)的平方=0,则(x+y)(x-Y)=

x-y-3绝对值+(2x+2y+10)的平方=0X-Y-3=0X-Y=32X+2Y+10=0X+Y=-5(x+y)(x-Y)=3X(-5)=-15

二元一次方程:{3X=2Y,3X+4Y=36 {3X+4Y=10,4X+Y=9 {2X-Y=6,X+2Y=-2 {X+Y

{3X=2Y,3X+4Y=36X=2Y/3代入3X+4Y=362Y+4Y=36Y=6X=2*6/3=4{3X+4Y=10,4X+Y=9X=(10-4Y)/3代入4X+Y=94(10-4Y)/3+Y=9

已知x,y满足约束条件{2x+5y>=10,2x-3y>=-6,2x+y

在坐标系中先作2x+5y≥10对应的直线2x+5y=10,取直线上方区域;然后作2x-3y≥-6对应的直线2x-3y=-6,把y的系数变为正,可知取直线下方区域;最后作2x+y≤10对应的直线2x+y

解方程组:(x+3)(y-2)=(x-3)(y+10),(x+1)(y+3)=(x-2)(y+12)

.死算呗xy-2x+3y-6=xy+10x-3y-30,2x-y=4xy+3x+y+3=xy+12x-2y-24,3x-y=92式减1式,x=5,y=6

若10.5x-10=36-3y=14+A,求x和y的值

得数可以带A吗再问:可以,就是把A看做准确值带进去,帮帮忙,谢啦~~再答:依题意得10.5x-10=14+A,36-3y=14+A;则10.5x=24+A,3y=22-A;解得x=(48+2A)/21

一次方程组x=y+3 (10y+x)+(10x+y)=99 怎么解

x=y+3(1)(10y+x)+(10x+y)=99整理得:x-y=3(3)x+y=9(4)(4)-(3)得,2y=6∴y=3把y=3代入(1)得,x=3+3∴x=6∴原方程组的解是:x=6y=3

解方程组x+y/6+x-y/10=3,x+y/6+y-x/10=-1

①-②可得:x-y/10-y-x/10=4x-y/5=4x-y=20——③①+②可得:x+y/3=2x+y=6——④由③④可得:x=13,y=-7

解下列方程组:(1)4x+10y=36 15x-10y=8 (2)x-2y=3 3x-8y=13 (3)2x-y=6 x

(1)4x+10y=3615x-10y=8x=44/19,y=64/19(2)x-2y=33x-8y=13x=-1,y=-2(3)2x-y=6x+2y=-2x=14/5,y=-2/5(4)2x+3y=

已知x^2+y^2-2x+6y+10=0 求36x+y^3的平方根.

因为x^2+y^2-2x+6y+10=0所以x^2-2x+1+y^2+6y+9=0(x-1)^2+(y+3)^2=0所以x=1,y=-336x+y^3=36-27=9所以36x+y^3的平方根是3和-

解方程组 2x+y(y-2x)=9 (x+y)(x+y-3)=10

设X+Y=A,则由a(a-3)=10得出(a-5)(a+2)=0,得a=5或a=-2.然后再分2种情况分别代入前面方程式.就能求出X、Y分别是多少了我觉得我这方法是最好解的方法了.

解方程组 10(x-y)=3(x+y)+15 6(x+y)=4(2x-y)+16

这慢慢做不就好了,这么简单的式子

若10.5x-10=36-3y=14+A,则x=( ),y=( )

10.5x-10=36-3y=14+A10.5x-10=14+A10.5x=24+Ax=(24+A)/10.5x=(48+2A)/2136-3y=14+A22-A=3yy=(22-A)/3