c 输入一个数,计算1*2

这是我写的程序.希望对您有用.1.#includevoidmain(){intx,y,z,a,b,c;printf("输入一个三位数x\n");scanf("%d",&x);a=x/100;y=x-1

importjava.util.Scanner;publicclassA{//下面的方法是对单个数求阶乘,并返回publicstaticintjieCheng(intn){intsum=1;for(i

#include#includevoidmain(){inta,t,m,sum=0;couta;for(inti=0;i

你的"sum=+t;”不对啊,应该是"sum+=t".C代码如下：#includevoidmain(){intx,t;printf("Inputanumber(10000-99999):");scan

求和应当是：#include#includemain(){inti,up=0,down=0,data[10];for(i=0,i0)up+=data[i];elsedown+=data[i];}pri

#includeintmain(){inta,sum=0;scanf("%d",&a);while(a){sum+=a%10;a/=10;}printf("sum=%d\n",sum);return0

voidmain(){intn=0;inti=0;intsum=0;printf("pleaseinputn:\n");scanf("%d",&n);if(n

已经运行确认了：#includemain(){intavg,i,sum=0,a[11];printf("请输入十个整数\n");for(i=1;i

#includeintmain(){inta;intsum=0;scanf("%d",&a);if(a

D楼主给分再问：为什么再答：（-1）平方+1=22平方+1=5

代码：#include <stdio.h>int sum(int n){\x05int s = 0;\x05while(n>

#include "stdio.h"#include "math.h"int main(){  float&n

#includevoidmain(){inta;printf("请输入一个三位数：");scanf("%d",&a);printf("各位数上的乘积为：%d\n",(a/100)*(a%10)*(a/

for{i=i;i再问：printf印出n!=%d*%d*%d*%d*%d...=%d可是我不知道要如何写才能分解成1X2X3X4X5...这样的,例如我输入8,我想印出1X2X3....X8=%d这

1~C2~B

//1设计一个程序,输入123,返回1+2+3也就是三个数的和6,输入-123也还是三个数的和,是6.#include<stdio.h>intadd(intn){  &

#include#include#defineE2.7182voidmain(void){floatx;floaty;scanf("%d",&x);if(x>=-1)y=pow(x,2)+1;

#includevoidmain(){floata=0,b=0,c=0;chard;printf("输入两个数:\n");scanf("%f%f",&a,&b);getchar();printf("选

#include<stdio.h>/**Author: QCQ*/long factorial(int number);void printout(

intvalues[10];intinput(){inti=0;printf("input10numbers:\n");for(i=0;i{scanf("%d",&values[i]);}return