c 编程求出[900,1000]之间有偶数个

#includeintmain(){inta,b;scanf("%d%d",a,b);if(a>b)printf("%d",a);elseprintf("%d",b);return0;}

#includevoidmain(){intsum=0;inti;for(i=1;i再问：main(){inti,a,b,c;a=0,b=0,c=0;for(i=1;i

#includemain(){\x09ints0=0,s1=0,i;\x09for(i=2;i

for(i=10;

=[22.32.52.733.23.53.84];C=[721501952803805107359801250];GeneralmodelPower1:f(x)=a*x^bCoefficients(w

额还没解决?你是刚学C?好吧基本没啥问题了,不过给你指几个问题：1.main函数没返回类型；2.i=i*i这句有问题,这里i都变了,后面再i++的话情何以堪；3.c=i%100,c你是想取百位数吗?那

如果是纯C应该是下面这样的#include"stdio.h"intmain(){inta[5][5]={{1,2,4,4,5},{1,3,5,7,9},{2,4,6,8,10},{6,7,8,9,10

#includeintmain(){inta;inti;intresult=1;printf("请输入一个奇数\n");scanf("%d",&a);if(a%2==0)printf("这不是奇数\n

#includevoidmain(){\x09inti,m,s;\x09m=1;\x09s=0;\x09for(i=1;i

inti=2123;intone,two,three,four;one=i%10;//各位two=(i/10)%10;//十位three=(i/100)%10;//百位four=(i/1000)%10

#inclludemain(){inta[]={3,1,5,9,6,2};inti.j,max,sum=0;max=a[0];for(i=0;imax)max=a[i];sum+=a[i];}prin

#includevoidmain(){inta,b,c,max,min;printf("请分别输入a,b,c三个数:\n");scanf("%d%d%d",&a,&b,&c);max=min=a;if

charc;scanf("%c",&c);intvalueC=(int)c;printf("%d\n",valueC);

#includeintmain(){\x09intx,y,z,i=0;\x09for(x=0;x

#includeintmax(intn);voidmain(){inta,b;printf("Pleaseinputnumber,endof-1:");scanf("%d",&a);while(a!=

#include"stdio.h"main(){inta=0,b=0,c=0,d=0;printf("请输入两个整数：");scanf("%d,%d",&a,&b);if(b==0)printf("输

我来#include#include"stdlib.h"#include"time.h"main(){inti,j,*p,arry[3][4];p=arry[0];srand((unsigned

#includevoidmain(){inti,s=0;for(i=1;i

#include#includevoidmain(){intn1,n2,n3,n;printf("所得的数为：\n");for(n=100;n

voidmain()intx,abs;printf("shurux");scanf("%d",&x);if(x>0)abs=x;elseabs=0-x;printf("jueduizhishi%d",