c 编写程序100到999各个位之和为x(x为一个正整数,要求在键盘上输入)
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#include <stdio.h>#include <stdlib.h>#include <string.h>#define&nbs
intmain(void){inti,ans;For(i=1;i再答:�������ټ�һ��#include再问:лл
//---------------------------------------------------------------------------#includeintmain(void){i
#includeintmain(){intn;scanf("%d",&n);do{printf("%d",n%10);}while(n/=10);printf("\n");return0;}
/>#include <stdio.h>int main(){\x09int n, cnt = 11;\x09scanf(&qu
1.res=((value>(15-n2+n1))=0){res=(value>n);}else{res=(value>>(siezeof(int)+n))|(value
矩阵加,减比较简单,循环一下所有对应元素就可以了.化上三角,下三角就可解线性方程式了,任务不轻,你也可以网上查找现成的.矩阵乘法,要先判断行列数是否符合乘法要求,再乘.下面给你矩阵乘法部分:#incl
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intmain(){inti=0;for(i=1;i
#includevoidmain(){intx,y,z,j=0;printf("一百只驴驮一百旦\n");for(x=0;x再问:有错误 if(z%2==0&&3*x+2*y
#include#includeintmain(){\x09inti,j;\x09unsignedseed;\x09inta[101];\x09printf("pleaseinputseed");\x
fpc:varn:string;a,b,i:longint;beginread(n);b:=0;a:=length(n);fori:=1toadob:=ord(n[i])-ord('0')+b;wri
#includeusingnamespacestd;#include/*编写程序,计算并输出下面数列前20项的和,结果取3位小数.(C++)2/1,3/2,4/3,5/4,6/5,7/6,8/7,……
#includeusingnamespacestd;intmain(){inti,j,k,num=0;for(i=1;i
#includemain(){inta,b;scanf("%d",&a);for(;a>=1;){b=a%10;printf("%d",b);a/=10;}printf("\n");}
main(){intn,i;doublee,p,t;printf("请输入n的值:");//这一语句在本例中没有作用,仅是依提示给出scanf("%d",&n);//这一语句在本例中没有作用,仅是依提
#includevoidmain(){\x09charstr1[30][10]={"zero","one","two","three","four","five","six","seven","eig
#include#includevoidmain(){floata,b,c,t,p,s;printf("请输入三边的长度\n");scanf("%f%f%f",&a,&b,&c);if(a>b){t=
输出结果哪里不对可以说下不?再问:有发代码的图片,有看见么?如果看不见的话,请看私信……拜托了~再答:#include"stdio.h"#include"time.h"#include"stdlib.
#include"stdio.h"intmain(){\x05inti,j,fenzi;\x05floatresult=0,fenmu;\x05for(i=1;i01:-1;\x05\x05for(f