c 用while将1到10所有素数打印出来
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![c 用while将1到10所有素数打印出来](/uploads/image/f/491516-44-6.jpg?t=c+%E7%94%A8while%E5%B0%861%E5%88%B010%E6%89%80%E6%9C%89%E7%B4%A0%E6%95%B0%E6%89%93%E5%8D%B0%E5%87%BA%E6%9D%A5)
#includelongmain(void){\x05longa[10]={0};\x05longi,sum1,sum2;\x05\x05printf("输入10个数以空格分隔:\n");\x05fo
publicstaticvoidmain(String[]args)throwsIOException{inti=0;intcount=0;while(i
Next循环SUM=0FORi=2TO100STEP2SUM=SUM+I;NEXTIwhile循环SUM=0i=2whilei
#includeintprint(intx){x&&print(x-1);x&&printf("%d",x);}intsum(intx){ints=0;x&&(s=x+sum(x-1));retur
您好!三种方式如下:1、for#includeintmain(){inti,n;doublesum=1;printf("请输入一个偶数;");scanf("%d",&n);for(;;)if(n%2!
#includevoidmain(){inti=0;sum=0;while(i
刚刚弄错了不好意思#includemain(){intsum=0,i=0;do{if(i%2==1)sum=sum+1;i++;}while(i
#includemain(){inti,n,sum;for(i=1,sum=0,n=1;i
先是for循环的:#include#includevoidmain(){inti,j,sign=0;doublek;for(i=1000;i
1do.while#includevoidmain(){inti,sum=1;i=1;do{sum=sum*i;i++;}while(i
while(m
PrivateSubForm_Load()DimiAsInteger,nAsLongDimkAsLongi=1:n=1DoWhilei
多谢sixiaoguai提醒.打惯C++了,一时改不过来.#includeintmain(){intn=300,i;intcounter=0;for(i=1;i
inti=2;do{if(i%2==0)/*各种不同的语言输出i,*/}while(i
/*用while语句语句求1到20的阶乘的和*/#include#defineN20voidmain(){inti,sum,sum1;sum=1;i=2;while(i
楼上的把循环条件中的n换成n/2,效率更好#includeusingnamespacestd;intmain(intargc,char*argv[]){intn,i,t,sum;cin>>n;i=2;
s=0;Do[s+=i,{i,100}];sFor[i=0;s=0,i
includemain(){inti,j=0;for(i=1;i
printf前面加一个‘}’
#include<stdio.h>int main(void){ int i = 100;