已知x的m-n次方除x的2n-1次方=x的11次方-搜答案-搜搜考试网

由于2x(M+3x)=6x^2y^2+N,所以2xM+6x^2=6x^2y^2+N比较可知2xM=6x^2y^2,6x^2=N所以M=3xy^2,N=6x^2

x^2m*x^2n=(x^m)^2*(x^n)^2=1/2^2*3^2=1/4*9=9/4x^(3m+2n)=x^3m*x^2n=(x^m)^3*(x^n)^2=1/2^3*3^2=1/8*9=9/8

解题思路：同底数幂的除法可解解题过程：已知xm=3xm+n=15求xn同学：以上解答如有疑问请在讨论中提出，祝学习进步！最终答案：略

x^(m-n)*x^(2n+1)=x^11.(m-n)+(2n+1)=11.m+n=10y^(m-1)*y^(4-n)=y^5.(m-1)+(4-n)=5.m-n=2(m+n)(m-n)=20m=6n

（4x的n+3次方-5x的n+2次方-3x的n+1次方）除5x的n+1次方=4x²/5-x+3/5当x=-5时原式=20+5+3/5=25.6

m!该多项式关于x的m次多项式

x^m=bx^n=b都等于b?应该是x^m=a则x^(3m-2n)=x^3m÷x^2n=(x^m)^3÷(x^n)^2=a^3/b^2

x^(m+n+1)=8m=2n+1x=2的话,n=1/3,m=5/3

x^(m-n)*x^(2n-1)=x^(m+n-1)=x^11m+n-1=11y^(m-1)*y^(4-n)=y^(m-n+3)=y^7m-n+3=7相加2m+2=18所以m=8n=m+3-7=4再问

1.(1)x^(2m＋3n)＝(x^2m)(x^3n)＝(x^m)²(x^n)³＝2²×3³＝4×27＝108(2)x^2m＋x^3n＝(x^2m)＋(x^3n

（m+n)x^ny^(m-2)（3xy^2+5x^2y)=21x^my^(n+1)+35x^(m+1)y^n=7x^(m-1)y^(n-1)(3xy^2+5x^2y)m+n=7n=m-1m-2=n-1

已知x的n次方>0,x的2n+m次方=171,x的m次方=19,x的2n次方=x的（2n+m）次方÷x的m次方=171/19=9;∵x的n次方>0∴x的n次方=3;∴x的3n次方=3³=27

m-n+2n+1=11m-1+4-n=7m+n=10m-n=4∴m=7n=3

因为x的m-n次方×x的2n+1＝x^(m-n)*x^(2n+1)=x^(m+n+1)=x的11次方所以m+n+1=11,因为y的m-1次方×y的4-n次方=y^(m-1+4-n)=y^(m-n+3)

设函数y=a^x+1/a^x(a>0)题目转化为,即证此函数为递增函数设0

x^(2m+2n)*x^(3m-2n)=8*4x^(2m+2n+3m-2n)=32x^5m=2^5(x^m)^5=2^5x^m=2x^(2m+2n)=8x^2m*x^2n=8(x^m)^2*x^2n=

x的m+k+3n次方等于x的m次方×x的k次方×（x的n次方）³=9×4×2²=288

x的3n=27x的m+2n次方＝x的m次方×x的2n次方＝4×9＝36

m-1=n.①m+n=0.②①代入②求得m=0.5n=-0.5

1.x^2m+x^3n=(x^m)^2+(x^n)^3=4+27=312.(1)3^30=(3^3)^10=27^10,4^20=(4^2)^10=16^10,所以3的30次方>4的20次方>5的10