已知p=x-y分之x平方-x-y分之x平方
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3x^2+xy-2y^2=(3x-2y)(x+y)=0x=-2y/3,或x=-y但由于你要求的式子中分母里有X平方-Y平方x=-y舍去其他就代入吧
令x=y+3变成x-y=3把x-y=3带到x-y里4分之一(x-y)的平方-0.3(x-y)+0.75(x-y)的平方+10分之3(x-y=2.25-0.9+6.75+0.9=9
(x-y)/(x+y)=(x-y)(x+y)/[(x+y)^2]=(x^2-y^2)/[x^2+y^2+2xy]=2xy/[x^2+y^2+x^2-y^2]=2xy/(2x^2)=y/xx^2-y^2
x^2+y^2-4x-6y+13=0(x^2-4x+4)+(x^2-6y+9)=0(x-2)^2+(y-3)^2=0所以(x-2)^2=0,(y-3)^2=0x-2=0,y-3=0x=2,y=3xy/
x/y=7/2(x²-3xy+2y²)/(x²+2xy+y²)=[(x/y)²-3(x/y)+2]/[(x/y)²+2(x/y)+1]=[(
已知5x-4y=0,切xy≠0,x/y=4/5;求(x平方-y平方)分之(x平方+y平方)-(x-y)分之(x+y)的值=(x²+y²)/(x²-y²)-(x+
x/y=1/2y=2x(x^2+2xy+y^2)/(x^2-xy+y^2)=(x^2+2x*2x+(2x)^2)/(x^2-x*2x+(2x)^2)=9x^2/3x^2=3
y分之x=2分之1y=2x所以原原式=(x²-2x²-8x²)分之(x²+4x²+4x²)=-9分之9=-1
y=2x/3则xy=2x2/3y2=4x2/9所以原式=(2x2/3)/(x2+4x2/9)-(4x2/9)/(x2-4x2/9)=(2/3)/(1+4/9)-(4/9)/(1-4/9)=6/13+4
因为x²+y²-4x+2y+5=0所以(x²-4x+4)+(y²+2y+1)=0所以(x-2)²+(y+1)²=o所以x=2y=-1所以下面
x的平方+2xy+y的平方分之x的平方-y的平方=(x+y)(x-y)/(x+y)²=(x-y)/(x+y)∵x+y=2,x-y=1∴原式=1/2
x的平方+xy+y的平方=0x的平方+y的平方=-xyx/y+y/x=-1如追加其它问题,采纳本题后点击想我求助,
P=(x²-y²)/(x-y)=(x+y)(x-y)/(x-y)=x+yQ=x²+2xy+y²-2xy-2y²=x²-y²所以x=
2x²-xy-3y²=0(x+y)(2x-3y)=0x=-y(舍去)或x=3y/2x/y=3/2x/y-x²/(x-y)=x/y-x²/(x²-2xy
还有下面这种方法7x平方-y平方分之x平方-2xy+3y平方分子分母同时除以y²=[(x/y)²-2(x/y)+3]/[7(x/y)²-1]=(4/9-4/3+3)/(2
(x+y)/(x-y)=3/2[(x/y)+1]/[(x/y)-1]=3/23(x/y)-3=2(x/y)+2x/y=5y/x=1/5(x^2+y^2)/xy=x/y+y/x=5+1/5=26/5
y分之x=2分之1y=2x所以原原式=(x²-2x²-8x²)分之(x²+4x²+4x²)=-9分之9=-1
∵圆x^2+y^2-4x-6y+12=0即(x-2)^2+(y-3)^2=1∴圆心(2,3),半径r=1∵p(x,y)是圆上任意一点又∵y/x为PO(O为原点)斜率k∵PO:y=kx当PO与圆相切时即
要求的其实可以看成是与椭圆相切的直线y=3x+z在y轴上面的最大最小截距.把y=3x+z代入椭圆方程得到16z^2+96xz+169x^2-400=0解这个方程得出范围.另外还有x取值范围是(-4,4
1.整理得到算式[2x-x+y]/[x^2-y^2]=[x+y]/[x+y][x-y]=1/[x-y]代入得到1/72.整理得到[1-3/(a+2)]/[(a^2-2a+1)/(a^2-4)]=[(a