已知a平方-3a 1=0求a平方除以a的4次方 1

a²-3a=-1a的立方-a的平方-5a+2007=a(a²-3a)+2a²-5a+2007=-a+2a²-5a+2007=2(a²-3a)+2007

3a²+ab-2b²=0两边同除以a²得3+b/a-2(b/a)²=0解得b/a=-1或b/a=3/2a/b-b/a-(a²+b²)/(ab

∵a的平方-3a-1=0a-3-1/a=0a-1/a=3(a-1/a)²=3²a²-2+1/a²=9∴a²+1/a²=11

a的平方-4a+1=0等式两边同除aa-4+1/a=0a+1/a=4因为a+1/a=4所以(a+1/a)^2=4^2a^2+2+1/a^2=16a^2+1/a^2=16-2=14(a-a分之一)的平方

已知a²+3a+1=0,求3a³+(a²+5)(a²-1)-a(5a+6)3a³+(a²+5)(a²-1)-a(5a+6)=a&s

先说一下思路：既然知道了a^2+a-1=0,就要对原式进行变形,变形的目的就是配凑出“a^2+a-1”.于是,a^3+3a^2+a-4=a*(a^2+a-1)+2*(a^2+a-1)-2=-2.

a^2-3a+1=0等式两边同时除以a,得a-3+1/a=0,即a+1/a=3a^2+1/a^2=(a+1/a)^2-2(完全平方公式)=3^2-2=7

a平方+3a-1=0,a≠0,两边同除以a得:a+3-1/a=0a-1/a=-3(a-1/a)²=9a²+1/a²-2=9a²+1/a²=11(a+1

由a^2+a-3=0得a^2+a=3a^3+2a^2-2a+1=a^3+a^2+a^2-2a+1=a(a^2+a)+=3a+a^2-2a+1=a^2+a+1=3+1=4

把a^2-3a+1=0两边都除以a,得,a+1/a=3所以(a-1/a)^2=a^2+1/a^2-2=(a+1/a)^2-4=3^2-4=9-4=5

a²-3a+1=0两边除以aa-3+1/a=0a+1/a=3两边平方a²+2+1/a²=9a²+1/a²=7

a^2-5a+1=0,a+1/a=5a^4+a^2+1/a=a(a^3+a+1/a+1/a^3)-1=a((a+1/a)^3-2(a+1/a))-1=a(5^3-2*5)-1=115*a-1a^2-5

a²-5a+1=0a²+1=5a平方(a²+1)²=25a²a^4+2a²+1=25a²a^4+a²+1=24a

a平方-4a+1=0a^2+1=4a(a^2+1)^2=16a^2a^4+1+2a^2=16a^2a^4+1=14a^2(a的4次方+a平方+1)/a^2=(14a^2+a^2)/a^2=15a^2/

(a²+b²-1)²=9(a²+b²-1)²-9=0(a²+b²-1-3)(a²+b²-1+3)=0

由题目知道a^3+a^2=a,a^2+a=1上面两个式子相加得a^3+2a^2=1所以a^3+2a^2+3=1+3=4

a平方-5a+1=0两边除以a得a-5+1/a=0a+1/a=5两边平方得∴a²+2+1/a²=25两边乘以3得3a²+6+3/a²=75两边减去5得3a

a平方+4a+1=0∴a+4+1/a=0∴a+1/a=-4两边平方得a²+2+1/a²=16a²+1/a²=14(3a的三次方+a平方+3a)分之（a四次方+a

a^2-3a+1=0等式两边同除以aa-3+1/a=0a+1/a=3a^2+1/a^2=(a+1/a)^2-2=3^2-2=7(a-1/a)^2=(a+1/a)^2-4=3^2-4=5再问：倒着的尖的

a+1/a=2(a+1/a)^2=a^2+1/a^2+2=4a^2+1/a^2=4-2=2a^2-3a+1=0a+1/a=3(a+1/a)^2=a^2+1/a^2+2=9a^2+1/a^2=9-2=7