已知(x-3)(x-4)分之2x 1-搜答案-搜搜考试网

再问：请问经过和结果怎么写？再答：

A/(x-5)+B/(x+2)=(5x-4)/(x^2-3x-10)左边＝A(x+2)/(x-5)(x+2)+B(x-5)/(x-5)(x+2)＝(Ax+2A+Bx-5B)/(x^2-3x-10)所以

x^2/(x^4+x^2+1)分子分母同时除以x^2,得：=1/(x^2+1+1/x^2)=1/[(x+1/x)^2-2+1]=1/(9-2+1)=1/8

因为A(x-2)+B(x-1)=3x-4所以A+B=3,2A+B=4A=1,B=2

A/(x-3)+1/(x+4)=[A(x+4)+(x-3)]/(x-3)(x+4)=(Ax+4A+x-3)/(x-3)(x+4)=[(A+1)x+(4A-3)]/(x-3)(x+4)∵(2x+1)/(

（x-1)（x-2)分之3x-4=x-1分之A+x-2分之B同乘以x-1,令x=1得A=1,同乘以x-2,令x=2得B=2所以（A-B）的2012次方=（-1）的2012次方=1

1/X(X+1)+1/(x+1)(x+2)+.+1/(x+99)(x+100)=1/x-1/(x+1)+1/(x+1)-1/(x+2)+.+1/(x+99)-1/(x+100)=1/x-1/(x+10

解题思路：先解方程求出x，再化简另一分式并把x值代入计算即可解题过程：解：经检验是原方程的解。

x=-3/4带进去算

由于A/(X+6)+B/(X-3)=(AX-3A+BX+6B)/(X+6)(X-3)=(2X+1)/(x+6)(x-3)所以,A+B=2,6B-3A=1,解得,A=11/9B=7/9

3+3x>5x-14>2xx-4x>-5x+5>0|x+5|=x+52>x>-5|x-2|+|x+5|=2-x+x+5=7

x/(x^2+x+1)=-1/2即-2x=x^2+x+1x^2+3x+1=0(x-1)/(2x^2+x^3-1)/(x^2-x+1)=(x-1)/(2x^2+x^3-1)(x^2-x+1)=(x-1)

x+1\x=3等式两边平方得x^2+1/x^2+2*x*(1/x)=3^2,则^2+1/x^2=9-2=7(x^2)/(x^4+x^2+1)=1/(x^2+1+1/x^2)=1/(7+1)=1/8

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[(x-2)分之3x-(x+2)分之x]乘x分之(x²-4)=[(x-2)分之3x]乘x分之(x²-4)-[(x+2)分之x]乘x分之(x²-4)=3(x+2)-(x-2

不用也可以算(x^4+x^2+1)/x^2=x^4/x^2+x^2/x^2+1/x^2=x^2+1+1/x^2你说的不对这里没有x+1/x而是x^2+2+1/x^2这个是完全平方即x^2+2*x*1/

(3x+4)/（x-2）（x+3）=A/(x-2)+B/(x+3)(3x+4)/（x-2）（x+3）=(Ax+3A+Bx-2B)/（x-2）（x+3)则：Ax+3A+Bx-2B＝3x+4(A+B)x+

（1）（x²-9分之x+3+6+x-x²分之x)乘4x-6分之3-x=[(x+3)/(x+3)(x-3)-x/(x+2)(x-3)]×(3-x)/2(2x-3)=[(x+2-x)/

(x+2/x)=4所以x^2+4+4/x^2=16x^2+4/x^2=12而(x-2/x)^2=x^2-4+4/x^2=8所以x-2/x=±√8=±2√2

2x-2/x=32x^2-3x-2=0x1=-1/2x2=2x^4+1/x^4=1/16+16=157/16x^4+1/x^4=16+1/16=157/16