9m-104(3m-7) 23=0中m的值是多少-搜答案-搜搜考试网

等差数列求和,每三项合并,有668项,就可以用一加二一直加到一百的方法算了

原式=9-m2+m2-6m-7=-6m+2=-6*1/2+2=-1

原式=4/(m-3)-2(m-3)/(m-3)²=4//(m-3)-2//(m-3)=2//(m-3)=2/(7-3)=1/2

2^(2m+6)×2^(3m)÷2^(4m+7)=162^(2m+6+3m-4m-7)=2^42m+6+3m-4m-7=4m=5再问：我第一个式子打错了再答：采纳我，重新问

3m-4n=7则3m=7+4n代入得：9m-10n+23=03×（7+4n）-10n+23=021+12n-10n+23=02n=-44n=-22则3m=7+4×（-22）3m=-81m=-27

(m+3m+5m+7m+.+2009m)-(2m+4m+6m+.+2008m)=(1+3+5+7+.+2009)m-(2+4+6+.+2008)m=【(1+2009)×1005÷2-（2+2008）×

9m+3×27m+1÷34m+7=81，32m+6×33m+3÷34m+7=8132m+6+3m+3-4m-7=34m=2，故答案为：2．

1.9=3^2,27=3^3,81=3^4,即:3^2m*3^3m*3^4m=3^18,3^(2m+3m+4m)=3^182m+3m+4m=18,解得,M=22.(X-Y)^3=-(Y-X)^3,结果

根号(3m+1)(2-m)=根号3m+1*根号2-m成立可得-1/3

yarandewo：(3+m)(3-m)+m(m-6)-7=9-m²+m²-6m-7=9-6m-7=2-6m∴当m=1/2时,原式=2-6×(1/2)=2-3=-1

(m-2n)/(2m+n)=3m-2n=6m+3n5m+5n=0m=-n[3(m-2n)/(2m+n)-(m-2n)/[2(2m+n)]-{9(m-2n)/[4(2m+n)]}=[3(-n-2n)/(

m-2m-3m+4m-5m-6m+7m.2004m=(1-2-3+4-5-6+7-8-9+...2002-2003-2004)m=(-4-7-10-..-2005)m=-(4+7+10+..+2005

（m2013m）*1007/2－（2m2012m）*1006/2=1007m

=m+(3m-2m)+(5m-4m)+……+(2015m-2014m)=m+1007m=1008m

(1+3+5+...+2011)m-(2+4+6+...+2010)m=(1+(3-2)+(5-4)+...+(2011-2010))m=1+1+1+...+1从2到2010是2010/2=1005项

有规律的,自己仔细看看～

我怀疑你少一个平方m/(m+3)-6/(m-9)÷2/(m-3)=m/(m+3)-6/(m+3)(m-3)×(m-3)/2=m/(m+3)-3/(m+3)=(m-3)/(m+3)当m=-2时原式=(-

2m+m(3+2007)*1003/2=2m+1008015m=1005017m

3m^2-m-[7m-2(4m-5)+9m^2]=3m^2-m-(7m-8m+10+9m^2)=3m^2-m-7m+8m-10-9m^2=-6m^2-10