6分之x+9分之x=50%

(1+4/5)x=9/16x=5/16(1-7/15)x=14/25x=21/10(1+3/4)x=5/6x=10/21

X(X+3)(x+6)分之(x+6)+x(x+3)(x+6)分之x+(x+6)(x+9)分之1X(X+3)(x+6)分之(2x+6)+(x+6)(x+9)分之1x(x+6)分之2)+(x+6)(x+9

请加括号再问：没有括号再答：是这样吗？x/(x-2)+x/(x-7)-9=x/(x-1)+1+x/(x-6)-8再问：是：x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(

x-10分之1+x-6分之1=x-7分之1+x-9分之1(x-6+x-10)/(x²-16x+60)=(x-7+x-9)/(x²-16x+63)(2x-16)/(x²-1

x：7分之4=3分之1x=1/3×4/7x=4/218分之15：x=2分之3x=15/8÷3/2x=5/46分之1÷10分之9=5分之2：x5/27=2/5：xx=2/5÷5/27x=54/25

1/3[1/x--1/(x+3)]+1/3[1/(x+3)--1/(x+6)]+1/3[1/(x+6)--1/(x+9)]=1/(x^2+18)1/x--1/(x+9)=3/(x^2+18)(x+9)

35/127/124/151/18

希望能帮上忙,第一步x-7/x-9+x-3/x-5=x-4/x-6+x-6/x-8第二步(x-9)+2/x-9+(x-5)+2/x-5=(x-6)+2/x-6+(x-8)+2/x-8第三步1+2/x-

由(x-4)/(x-5)-(x-5)/(x-6)=(x-7)/(x-8)-(x-8)/(x-9)得：（X-4）/（X-5）-（X-7）/（X-8）=（X-5）/（X-6）-(X-8）/（X-9）即：【

因为(x-4)/(x-5)=[(x-5)+1]/(x-5)=1+1/(x-5)……所以原方程可化为1+1/(x-5)-1-1/(x-6)=1+1/(x-8)-1-1/(x-9)1/(x-5)-1/(x

交你方法吧,不然遇到同样问题还是不会,以第一题为例通分,通过分子分母乘以相同数字的办法,将分母搞成一致30分之6x-30分之5x=30分之1去分母,两边同时乘以分母6x-5x=1x=1自己试作做其他的

因为(x-4)/(x-5)=[(x-5)+1]/(x-5)=1+1/(x-5)……所以原方程可化为1+1/(x-5)-1-1/(x-6)=1+1/(x-8)-1-1/(x-9)1/(x-5)-1/(x

(x-4）/(x-5)-(x-5)/(x-6)=(x-7)/(x-8)-(x-8)/(x-9)对方程两边各自通分：[(x-4)(x-6)-(x-5)(x-5)]/[(x-5)/(x-6)]=[(x-7

9分之1=3分之x-6分之19分之1乘9=3分之x乘9-6分之1乘91=3X-2分之33X=-3分之2-1X=-9分之2-3分之1X=-9分之5

每个分式减去1(x-4-x+5)/(x-5)+(x-8-x+9)/(x-9)=(x-7-x+8)/(x-8)+(x-5-x+6)/(x-6)1/(x-5)+1/(x-9)=1/(x-8)+1/(x-6

7/x(x+1)-6/(x+1)(x-1)=-1/x(x-1)两边乘以x(x+1)(x-1)得7(x-1)-6x=-(x+1)7x-7-6x=-x-12x=6∴x=3经检验：x=3是方程的解

X(X+3)分之1+(X+3)(X+6)分之1+(x+6)(X+9)分之1=2(X+9)分之33{1/x-1/(x+3)+1/(x+3)-1/(x+6)+1/(x+6)-1/(x+9)}=3/(2(x

6分之x+9分之X=5(1/6+1/9)x=5(5/18)x=5x=5÷5/18x=18

原式=6/x^2-9-x-1/6-x2=1/2即12+(x-1)(x+3)/2(x+3)(x-3)=1/2即(x-3)(x+4)=0∴x=3(舍)或x=-4很高兴为您解答,【学习宝典】团队为您答题.请

(x+7)/(x+6)+(x+9)/(x+8)=(x+10)/(x+9)+(x+6)/(x+5)1+1/(x+6)+1+1/(x+8)=1+1/(1+9)+1+1/(x+5)1/(x+6)+1/(x+