搜搜考试网3 x-5[2x-7]=3解方程
来源：学生作业帮助网 编辑：作业帮 时间：2024/06/17 00:43:11
![3 x-5[2x-7]=3解方程](/uploads/image/f/273229-61-9.jpg?t=3+x-5%5B2x-7%5D%3D3%E8%A7%A3%E6%96%B9%E7%A8%8B)
(x+3)/(x+2)+(x+9)/(x+8)=(x+5)/(x+4)+(x+7)/(x+6)1+(x+5)/(x+2)(x+8)=1+(x+5)/(x+4)(x+6)x=-5再问：第二步那个1是怎么
2（x-2)(x+3)-(2x-5)(x-1)=3x+72（x²+x-6）-（2x²-7x+5）=3x+72x²+2x-12-2x²+7x-5=3x+79x-1
2x+3x+5x=3210x=32x=3.2
((X-2)(X-4)-(X-3)^2)/(X-3)(X-4)=((X-5)(X-7)-(X-6)^2)/(X-6)(X-7),-1/(X^2-7X+12)=-1/(X^2-13X+42),6X=30
x(2x-4)+3x(x-1)=5x(x-3)+82x²-4x+3x²-3x=5x²-15x+88x=8x=1
我给个思路吧（X+2-1/X+2)-(X+3-1/X+3)=（X+6-1/X+6)-(X+7-1/X+7)1-1/(X+2)-1+1/(X+3)=1-1/(X+6)-1+1/(X+7)剩下的就自己解决
x1=1/3(10-7(2/(1357-9√[22717]))^(1/3)-(1/2(1357-9√[22717]))^(1/3));x2=10/3+1/6(1+i√[3])(1/2(1357-9√[
7x-2x+3x=365x+3x=368x=36x=4.5
再问：2x是怎么得来的
x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)
通分化简得到(x+1)(x+2)=(x+5)(x+6)3x+2=11x+308x=-28x=-7/2
（7-2+3）X=368X=36X=9/2
首先由题意得x+1≠0,x+7≠0,x+5≠0,x+3≠0,即x≠-1,x≠-7,x≠-5,x≠-3,则先简化方程(x+1+1)/(x+1)+(x+7+1)/(x+7)=(x+5+1)/(x+5)+(
(x-3)(x+8)=(x+4)(x-7)+2(x+5)x²+5x-24=x²-3x-28+2x+105x+3x-2x=24-28+106x=6x=1
2(x-3)(x+5)=x^2+(x+2)(x-2)+(x+7)2(x^2+2x-15)=x^2+x^2-4+x+72x^2+4x-30=2x^2+x+33x=33x=11
(1/x-7)+(1/x-1)=(1/x-6)+(1/x-2)1/(X-7)-1/(X-6)=1/(X-2)-1/(X-1)(X-6-X+7)/[(X-7)(X-6)]=(X-1-X+2)/[(X-1
这个展开就行了哇.2*（x^2+x-6）-(2*x^2-7X+5)-3x-7=0化简得：6X=24x=4应该是对的.嘿嘿.
(x+1)(x-3)=2x+5x²-2x-3=2x+5x²-4x=8x²-4x+4=8+4(x-2)²=12x-2=±2√3x=2-2√3,x=2+2√3
解方程：(x-2)(x^2-6x-9)=x(x-5)(x-3)将方程展开：X^3-6x^2-9x-2x^2+12x+18=x^3-8x^2+15x合并同类项得：12x=18则x=18/12=3/2