2x2-4x-1=0怎么解
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设(x²-1)/(x²+2x)=t则8t+3/t=118t²-11t+3=0(8t-3)(t-1)=0解得t=3/8或t=11.t=3/8(x²-1)/(x
后面的x²+11x-708有误吧!再问:没有题目就这样能不能帮我再答:那我就试试:原式为:1/x2+x+1/x2+3x+2+1/x2+5x+6+1/x2+7x+12+1/x2+9x+20=5
1、x^2+4x=10(x+2)^2-4=10(x+2)^2=14(x+2)=正负根号14x=(正负根号14)-22、x^2-6x=11(x-3)^2-9=11(x-3)^2=20(x-3)=正负2倍
可以分两步走1、当2x-1≥0x≥1/2则x^2-(2x-1)-4=0x^2-2x+1-4=0x^2-2x-3=0(x-3)(x+1)=0x=3x=-1(舍)x=32.当2x-1<0x<1/2x^2-
原式可化为1/(x+1)(x-3)+2/(x-3)((x+2)+3/(x+1)(x+2)=0两边同乘以:(x+1)(x+2)(x-3)得:(x+2)+2(x+1)+3(x-3)=0(x≠-1,x≠-2
(1)x2+4x+4=1+4,∴(x+2)2=5,∴x+2=±5,∴x1=5-2,x2=-5-2;(2)整理得2x(x+3)-(x+3)=0,∴(x+3)(2x-1)=0,∴x+3=0或2x-1=0,
(1)4x2-3x=52移项得,4x2-3x-52=0,(x-4)(4x+13)=0,x1=4,x2=-134.(2)5x2=4-2x原方程可化为5x2+2x-4=0,a=5,b=2,c=-4,△=4
2x+5x+3+4-x/2+2x+x-2=019x/2=-5x=-19/10检验:带入x是、原式=0
x2+x+1=2/(x2+x)(X²+x)²+(x²+x)-2=0(x²+x+2)(x²+x-1)=0∴x²+x-1=0x=(-1±√5)/
两边乘x(x+1)(x-1)2(x-1)+3(x+1)=4x2x-2+3x+3=4x5x+1=4xx=-1经检验,x=-1时分母x+1=0增根,舍去方程无解
(x²+x)(x²+x-2)=-1把(x²+x)看成整体(x²+x)[(x²+x)-2]=-1运用乘法分配率(x²+x)²-2(x
x²+x-1/(x²+x)=3/2两边同时乘以(x²+x)得:(x²+x)²-1=3(x²+x)/22(x²+x)²-3
x²+2x+1=10(x+1)²=10x+1=3或x+1=-3所以x=2或x=-4【(x²+4)/x-4】÷【(x²-4)/(x²+2x)】=【(x&
通分:(x^2-3x)+(2x-1)(x+1)=0化简:3x^2-2x-1=0x1=1(舍去,分母不为0)x2=-1/3
(x+1)2=32,解得x1=-1+62,x2=-1-62.
令(x^2-1)/x=t3/t+t/2=5/2t^2-5t+6=0t=2或t=3即:(x^2-1)/x=2或(x^2-1)/x=3x^2-2x-1=0或x^2-3x-1=0x=1±√2或x=(3±√1
(x-4)/(x²+x-2)=1/(x-1)+(x-6)/(x²-4)(x-4)/(x-1)(x+2)=1/(x-1)+(x-6)/(x-2)(x+2)(x-4)(x-2)=(x-
2/x2=30=0x=±1/√15再问:过程再答:合并同类项1/x2+1/x2+1/x2+2x+11x-13x+10+10+10=03/x2+30=010x2+1=0x==±√10i/10刚才答案有误
解题思路:利用一元二次方程计算解题过程:最终答案:略