化简-3xy除以2y^2 3x
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/05 19:38:47
由X+Y=3XY可得X+Y-XY=2XY,用X+Y-XY替换分母中的2XY,所以(2X+2Y-XY)/(X+Y+2XY)=(2X+2Y-XY)/(2X+2Y-XY)=1
原式=[x²-4xy+﹙2y﹚²-1]/﹙x-2y-1﹚=[﹙x-2y﹚²-1²]/﹙x-2y-1﹚=﹙x-2y+1﹚﹙x-2y-1﹚/﹙x-2y-1﹚=x-2
把3x+2y转化成分式.同时÷xy再算就行了
(x-y+x+y)/(x^2-y^2)*((x-y)^2/2x)=2x/(x-y)(x+y)*((x-y)^2/2x)=(x-y)/(x+y)x=根号3,y=负根号2原式=(根号3+根号2)/(根号3
^2代表平方,/代表分数线和除号由题意得设x=3k,y=2k(k不等于0)代入原式=(9k^2+18k^2)/(6k^2+8k^2)=27k^2/14k^2=27/14所以原式的值为14分之27.
【x的平方-2x】除以2y-xy=x(x-2)/[-y(x-2)]=-x/y
此题应该抄错了,应该是遗漏了一个x,∵xy/(x+y)=2∴1/x+1/y=1/2(3x-5xy+3y)/(-x+3xy-y)=(3x-5xy+3y)/(-x+3xy-y)[分子分母同除以xy,得]=
由于xy除以x+y=2故xy=2(x+y)将这代入8x-5xy+8y除以-x+3xy-y化简得其中的(x+y)会相互约去故8x-5xy+8y除以-x+3xy-y=-2/5希望这个能帮到你over~
9x^2/2y再问:貌似是负的吧再答:没看见前面的“负”…………
x的平方+3xy+2y的平方除以x的平方y+2xy的平方=(x+2y)(x+y)/xy(x+2y)=12/9=4/3再问:那个再问一下不改变分式的值使分式的分子分母首项系数都是正数-(负7xy/负8z
y-x-2xy=0(3x+xy-3y)/(y-xy-x)=(3x+6xy-5xy-3y)/(y+xy-2xy-x)=[-3(y-x-2xy)-5xy]/(y-x-2xy)+xy=(0-5xy)/(0+
1、x-2√xy-3y=(√x-3√y)(√x+√y)=0解得√x=3√y或者√x=-√y(舍去)也就是x=9y2x+y+√xy除以y-x-√xy=(2*9y+y+3√y*√y)/(y-9y-3√y*
=3xy×(-3x/2y)=-9x²/2
由题意得:xy=3(x+y)原式=[2x+2y-9(x+y)]%[-x-y+9(x+y)]=[-7(x+y)]%[8(x+y)]=-7/8(因为x+y不等于0)
x/3=y/4所以x=3y/4所以(x^2-xy)/(x^2+y^2)=(9y^2/16-3y^2/4)/(9y^2/16+y^2)=-3/25
[x(x^2y^2-xy)-y(x^2-x^3y)]除以3x^2y=(x³y²-x²y-x²y+x³y²)÷3x²y=(2x
可知x≥0,y≥0(x-y)/(√x+√y)-(x-2√xy+y)/(√x-√y)=(√x+√y)(√x-√y)/(√x+√y)-(√x-√y)²/(√x-√y)=(√x-√y)-(√x-√
(6x²y³)÷(3xy)=2xy²(3x²)²÷(3x)=(9x^4)÷(3x)=3x³
再答:再答:中间那个中间那个红框是原因
因式分解原式=[x(x-2)]/[-y(x-2)]=-x/y