化简,x乘以x加1分之1,
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x2+2+1/x=2(x+1/x)x2+2+1/x=2x+2/xx2-2x+2=1/x画图象,得x=1
(2x-5)/(x-2)(x-3)-1/(x-3)=(2x-5)/(x-2)(x-3)-(x-2)/(x-2)(x-3)=(2x-5-x+2)/(x-2)(x-3)=(x-3)/(x-2)(x-3)=
1/2x+3/4*4/5=11/2x=1-3/51/2x=2/5x=4/5x=五分之四
题目应是x-1分之1加(x-1)乘以(x-2)分之1加(x-2)乘以(x-3)分之1+……+(x-99)乘以(x-100)分之1=11/(x-1)+1/(x-1)(x-2)+1/(x-2)(x-3)+
原式=[(x+2)/x(x-2)-(x-1)/(x-2)²]*x/(x-1)(x-4)*(x-2)²=(x²-4-x²+x)/x(x-2)²*x/(x
原式=2(x+3)(x-2)/(x-2)²x(x+3)-1/(x-2)=2/x(x-2)-1/(x-2)=(2-x)/x(x-2)=-x
依题有(|m|/2-1)x=1因方程无解则必有|m|/2-1=0即m=±2
把(x+1)^2分之x^2拆开,变成1-2/(x+1)+1/(x+1)^2,积分加减法拆开(sinx+1),最后用分部积分法(把x+1分之一移到d后面)再问:1+x^2没有括号
原方程可化为:400*(0.75x)-99x=0.1300x-99x=0.1201x=0.12010x=1解得:x=2010分之1
解:2*[1-1/3(2x-1/3)]=3*[x/6-1/2*(-5x-10/3)]2*[1-2/3+1/9]=3*[x/6+5/2x+5/3]2*[1-2/3*x+1/9]=x/6+5/2*x+5/
原式=[3x/(x-1)-x/(x+1)]×[(x²-1)/x]={3x(x+1)/[(x-1)(x+1)]-x(x-1)/[(x-1)(x+1)]}×[(x-1)(x+1)/x]=[3x(
再问:很详细,已经看懂了非常感谢!可以再请教一道分解因式的题吗?3x的立方减18x的平方加27x再答:
是(x-y)分之(x+y)*(x+y)分之(x-y)如果是,那么:(x-y)分之(x+y)*(x+y)分之(x-y)=1
括号里通分,可以和括号外抵消等于2x+4
=[1/(x-3)-(x+1)/(x+1)(x-1)]×(x-3)=1-(x-3)/(x-1)=2/(x-1)
1乘以2分之x+2乘以3分之x+.+2012乘以2013分之x=2012(1-1/2+1/2-1/3+……+1/2012-1/2013)x=2012(1-1/2013)x=20122012/2013x
观察x/(1×2)=x/2而x-x/2=x/2则有x/(1×2)=x-(x/2)x/(2×3)=x/6而(x/2)-(x/3)=x/6则有x/(2×3)=(x/2)-(x/3)同理x/(3×4)=(x