判断一个数n(从控制台输入),能否同时被5和3整除,输出能够整除或不能整除.

importjava.util.Scanner;publicclassA{//下面的方法是对单个数求阶乘,并返回publicstaticintjieCheng(intn){intsum=1;for(i

static void Main(string[] args){    //声明变量    

#includeintmain(intargc,char*argv[]){inti,a,b,sum=0,c;scanf("%d%d",&a,&b);if(a>b){c=a;a=b;b=a;}for(i

Reverse

usingSystem;usingSystem.Collections.Generic;usingSystem.Linq;usingSystem.Text;namespacetest{classPro

//Note:YourchoiceisC++IDE#includeusingnamespacestd;longintSfun(constintN){longintsum=1;if(N==0||N==1

#includemain(){intn;printf("Pleaseenteranumber:");scanf("%d",&n);if(n%2==0)printf("Thenumber%dis偶数\n

页面代码请输入第一个数：请输入第二个数：请输入第三个数：计算三个数中最小的数是：js代码是functiongetnum(){varnumone=document.getElementById("tex

使用了数组的动态分配,看不懂的话我还有其他方案#include#includeboolprime(intnum){boolflag=true;if(num

publicintfn(intn){intsum=0,m=1;for(inti=1;i

varn,i,j,k:longint;t:boolean;beginreadln(n);ifn=1thenbeginwritelN('no');halt;end;t:=true;fori:=2totr

int[]num=newint[4];inti,j;inttemp;Console.WriteLine("请输入4个数");for(i=0;iConsole.WriteLine("第{0}个数",(i

staticvoidMain(string[]args)　　{　　stringstr="",math="";　　while(true)　　{　　boolIsOk=true;　　Console.Writ

staticvoidMain(string[]args){intintInput=0;while(true){Console.Write("请输入一个大于0的正整数：");stringstrInput

#includeintmain(){usingnamespacestd;intcint_a,cint_b,rint_c;charch;coutcint_b;while(!cin){coutcint_b

CLEARaccept"请输入N值："TONs=1FORi=1TOVAL(n)IFMOD(i,2)=0s=s*iENDIFENDFOR?"1——N中的所有偶数的积为："+ALLTRIM(STR(s))

importjava.util.Scanner;classtest7{publicstaticvoidmain(Stringargs[]){Scannerscan=newScanner(System.

#include#includevoidmain(){intfunc_sum(intn){intsum=1;for(inti=0;inum;cout

importjava.util.*;publicclassMath{publicstaticvoidmain(Stringargs[]){inta,b;Scannersc=newScanner(Sys

#includeusingnamespacestd;voidmain(){intnum[10];inti;intmax,smax;cout