先化简,再求值:a分之a 3乘a的平方 6a 9分之6
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/05 10:19:37
=[(a²-4)/(a-2)]×1/a(a+2)=[(a+2)(a-2)/(a-2)]×1/a(a+2)=(a+2)×1/a(a+2)=1/a
.(a-1分之3a剪a+1分之a)乘以a分之a²剪1=[3a/(a-1)-a/(a+1)]×(a+1)(a-1)/a=3a/(a-1)×(a+1)(a-1)/a-a/(a+1)×(a+1)(
题目应该是这样的吧?[a/(a-2)-a/(a+2)](4-a^2)/a那么原式=[a/(a-2)](2-a)(2+a)/a-[a/(a+2)](2-a)(2+a)/a=-(2+a)-(2-a)=-4
=(a-3)/2(a-2)÷[5/(a-2)-(a+2)(a-2)/(a-2)]=(a-3)/2(a-2)÷(5-a²+4)/(a-2)=(a-3)/2(a-2)×[-(a-2)/(a+3)
原式=(a-1)/(a+2)×(a+2)(a-2)/(a-1)²×(a+1)(a-1)=(a-2)(a+1)=a²-a-2∵a²-a=0∴原式=0-2=-2
(a-1)/(a+2)*(a^2-4)/(a^2-2a+1)÷1/(a^2-1)=(a-1)/(a+2)*(a+2)(a-2)/(a-1)^2*(a+1)(a-1)=(a+1)(a-2)=a^2-a-
(a-根号3)乘(a+根号3)-a(a-6)=a^2-(√3^2)-a^2+6a=6a-3当a=√5+1/2时,原式=6*(√5+1/2)=3+6√5
x=ax²+2x=1原式=1/(a+1)-(a+3)/(a+1)(a-1)×(a-1)²/(a+1)(a+3)=1/(a+1)-(a-1)/(a+1)²=(a+1-a+1
a-a/3+1-a+a/2-3/a²-a²/4-6a+9=-35a/6-3/a²-a²/4+10a取6,得-35-1/12-9+10=-34又1/12
(a+2a+1)/(a-1)-a/(a-1)=(a+1)^2/(a+1)(a-1)-a/(a-1)=(a+1)/(a-1)-a/(a-1)=1/(a-1)由a=根号3+1,所以原式=1/(a-1)=1
原式=(3+a)(3-a)/(a+3)^2x(a+3)/(a-3)a-1/a=-1/a-1/a=-2/a=-2/根号2=-根号2
答:a=1/(2+√3)=(2-√3)/[(2+√3)(2-√3)]=(2-√3)/(4-3)=2-√3所以:0
化简出来应该是ab(a²-1).很简单,因为a-4的绝对值为非负数,根号B-9也为非负数,所以两个个非负数之和等于0,两数必为0所以b为9,a等于4.带入就是36乘以15等于540.
再答:你不要像我这样画掉我这样只是为了方便我计算
a/(a-3)-(a+6)/(a²-3a)+3/a=(a²-a-6+3a-9)/a(a-3)=(a²+2a-15)/a(a-3)=(a-3)(a+5)/a(a-3)=(a
原式=-10a2-6a+6,将a=-2代入原式得:原式=-10a2-6a+6=-10×(-2)2-6×(-2)+6=-22.
原式=4a+3a2-3-3a3+a-4a3=-7a3+3a2+5a-3,当a=-2时,原式=56+12-10-3=55.
(a-2)分之a-(a²-2a)分之2a-a分之2=[a(a-2)]分之a²-[a(a-2)]分之(2a)-[a(a-2)]分之[2(a-2)]=[a(a-2)]分之[a²