使用循环累加100以内的偶数之和-搜答案-搜搜考试网

intsum=0;for(inti=1,i

#includeusingnamespacestd;voidmain(){inti,sum=0;for(i=2;i再问：i=2的话开始sum不应该等于1么？再答：最后输出的时候加了1，当然你在前面

store0tosume,sumofori=1to100ifi%2=0sume=sume+i&&偶数累加elsesumo=sumo+i&&奇数累加endifnext"1~100偶数累加和=",sume

publicclassTest{publicstaticvoidmain(String[]args){ints1=0;ints2=0;for(inti=1;i

dimheaslong,naslonghe=0n=1dohe=he+nn=n+1loopuntilln>100msgbox"累加和是："&he‘以上是VB的写法.

intn=0;intsum=0;while(n

Console.WriteLine("请输入起点整数");intnumberOne=Convert.ToInt32(Console.ReadLine());Console.WriteLine("请输入

#includevoidmain(){inti,sum=0;for(i=1;i

intsum=0;for(inti=0;i

unsignedchari;unsignedintsum;sum=0;for(i=2;i

an=(2n)^2=4n^2S50=4x50x51x101/6=171700

什么语言?如果是VB:DimsasIntegerDimiasIntegers=0Fori=0to100Step2'i从0数到100,每隔两个数字数一次,所以就是0,2,4,6,8,...,100s=s

偶数：2468101214161820.（n+2）奇数：1357911131517.（x+2）n表示2x表示1

method1sum=0;for（i=1;i再问：可以解释下你用了那三种循环语句结构再答：for循环dowhile循环while循环

summary = 0for i in xrange(10): n = int(ra

2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60,62,64,66,68,70

sum=0;form=1:1000sum=sum+m;endsum

参考代码：n=111;Y=cos(1:n);A=zeros(n,1);for k=1:n,A(k)=2/n*sum(Y.*sin(2*pi*(1:n)*k/n));endsubplot&nb

（2+100）*25=2550

#includemain(){inti,s=0;for(i=0;i