从键盘输入n个整数输入值为负值时结束输入

#includevoidmain(){\x09intn,i,j,t,a[10000];\x09printf("请输入正整数N:");\x09scanf("%d",&n);\x09printf("请依次

#includeusingnamespacestd;intmain(){inti,n,s=0;coutn;s=0;for(i=1;i

运行通过,有问题HI：#includeintmain(){intnum,n=0,m=0;do{scanf("%d",&num);if(num>0)m++;elseif(num

#include#includedoublefun(intn);intmain(){printf("Inputn:");intn;scanf("%d",&n);doubleS=fun(n);

#includeintmain(){intn,num,max,min;scanf("%d",&n);for(inti=n;i>0;i--){scanf("%d",&num);if(i==n)//初始化

#includevoidperm(int*data,intn,intcurr){if(curr==n-1){for(inti=0;iprintf("%d",data[i]);printf("\n");

VC6.0调试通过了,while循环结构#include"stdio.h"voidmain(){inti,sum=0,n;i=1;printf("Inputn:");scanf("%d",&n);wh

#include "stdio.h"int main(){   int count1=0,count2=0,i;&nbs

楼主你好!根据你要求实现如下#include<stdio.h>int fun(int n){ if(n>0)return n*fun(n-1)

#include#defineN30typedefstructstudent{\x09charname[10];\x09intscore;}STU;voidmain(){\x09STUs[N];\x0

#include<stdio.h> int getMaxNumber(int n)  { int k; 

#includevoidmain(){intn,i,j,k=0;scanf("%d",&n);printf(“这些数中奇数有:\n");for(i=0;i

我感觉这段程序完全对不上要求.首先凭空冒出一个x,其次按照这段程序,c应该是输出的倒序数字,但单凭c=b%10或c=b/10,而且其间输入数字b的值没有改变,显然无法实现倒序.我给出一个参考程序：ma

#includeintmain(void){intcount=0,n,sum=0;whlie(scanf("%d",&n)!=EOF){if(n==-1)break;elsesum+=n;count+

#include#includevoidmain(){intn,s,j,i;printf("inputn(n

#include<stdio.h>void main(){ int a[5]={0}; int i,j,t; printf(&q

BufferedReaderbuf=newBufferedReader(newInputStreamReader(System.in));System.out.print("请输入时间(注意格式必须为

用C语言吗再问：是的再答：#includeintmain(){inta=0,sum[4]={0,0,0,0};do{scanf("%d",&a);if(a==1)sum[0]++;if(a==2)su

#include<stdio.h>#include<stdlib.h>#include<string.h>typedef struct Link

intb[4];intsum=0;b[0]=a/1000;//千位b[1]=a%10;//个位b[2]=(a-b[1])%100;//十位b[3]=(a-b[0]*1000)/100;//百位for(