(6-2y)*(4-2y) (y-2)*(y 1)=0的解

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(6-2y)*(4-2y) (y-2)*(y 1)=0的解
1.5y+8y-6y=2y-3

移项、得1.5y=-3系数化为一、y=-2很简单的呀

解方程 2y+5/3y-6-y/2=5y-4/2y-4

2y+5/3y-6-y/2=5y-4/2y-42y+5/3y-1/2y-5y+2y=6-41/6y=2y=12

x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20

由(1)得3x+3y+2x-2y=365x+y=36(3)由(2)得4x+4y-3x+3y=-20x+7y=-20(4)(3)×7-(4)得34x=272∴x=8把x=8代入(3)得y=-4∴x=8y

{(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20

{(x+y)/2+(x-y)/3=63(x+y)+2(x-y)=36(1)4(x+y)-3(x-y)=-20(2)由(1)*3+(2)*2得9(x+y)+6(x-y)+8(x+y)-6(x-y)=36

{(z+y)(x-y)-(x-y)的2次方+2y(x-y)}除以4y

(x-y)(z+y-x+y+2y)÷4y=(x-y)(z-x+4y)÷4y{(x+y)(x-y)-(x-y)的2次方+2y(x-y)}除以4y=(x-y)(x+y-x+y+2y)÷4y=(x-y)(4

解分式方程6y+12/y^2+4y+4 -y^2-4/y^2-4y+4 +y^2/y^2-4=0

6y+12/y^2+4y+4-y^2-4/y^2-4y+4+y^2/y^2-4=0没有说明分母是那个分子是那个这样子很混乱建议加括号扩住分子分母再问:我现在加了括号再答:解6(Y+2)/(Y+2)^2

4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6

第二个方程是不是写错了2/(x+y)+3/(x-y)=6是这样吗

解方程:(y+4)/5+y+6=(y+8)/2-(y+4)/3

(y+4)/5+y+6=(y+8)/2-(y+4)/3乘以30得6(y+4)+30y+180=15(y+8)-10(y+4)6y+24+30y+180=15y+120-10y-406y+30y-15y

先化简,在求值:6y-(y+2分之y + 2-y分之y)除以y³-4y-2y²+8分之y,其中y=

6y-(y+2分之y+2-y分之y)除以y³-4y-2y²+8分之y=6y-[(2y-y²+2y+y²)/(4-y²)]÷y/(y-2)³=

4x-2y-6y*-y-3x+5y* *=2 就是平方

题意不清什么是平方,*吗?那么**代表三次方还是4次方呢

{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1

3(x+y)-4(x-y)=4(x+y)/2+(x-y)/6=1令a=x+y,b=x-y3a-4b=4(1)a/2+b/6=1则3a+b=6(2)(2)-(1)5b=2b=2/5a=(6-b)/3=2

4y(y-x)的2次方-6y(x-y)三次方 因式分解

4y(y-x)的2次方-6y(x-y)三次方=4y(x-y)²-6y(x-y)³=2y(x-y)²(2-3x+3y)【提取公因式2y(x-y)²】

解方程:2y+5/3y-6 — y/2 = 5y-4/2y-4

2y+5/3y-6-y/2=5y-4/2y-42y+5/3y-1/2y-5y+2y=6-41/6y=2y=12再问:是2y+5/3y—1/2y—5y+2y=6—4吗再答:是的,绝对正确的,刚刚有一位同

1.((y+2x)(-2x+y)+4(x+2y)^2)/3y 2.(2(x-y)^3-8(x-y)^2(x+y)+6y(

1.((y+2x)(-2x+y)+4(x+2y)^2)/3y=(y^2-4x^2+4x^2+16xy+16y^2)/3y=(17y^2+16xy)/3y=17y/3+16x/32.(2(x-y)^3-

x+2y+4y^2/x-y+4x^y/4y^2-x^2

“4y^2/x-y”应该是“4y^2/x-2y”吧x+2y+4y^2/x-2y+4x^2y/4y^2-x^2=(x+2y)+4y^2/(x-2y)+4x^2y/(2y-x)(2y+x)=(x+2y)+

解3y+5/3y-6=1/2+5y-4/2y-4

题目有误(1)若是(3y+5)/(3y-6)=1/2+(5y-4)/(2y-4),(3y+5)/(3y-6)=1/2+(5y-4)/(2y-4)两边同时乘以12(y-2),得(3y+5)x4=12(y

约分y^2+y-2/y^2+4y+4

解(y^2+y-2)/(y^2+4y+4)=(y+2)(y-1)/(y+2)^2=(y-1)/(y+2)

x+2y+4x^2y/4y^2+4y^2/x-2y

x+2y+4y^2/(x-2y)=((x+2y)(x-2y))/(x-2y)+4y^2/(x-2y)=(x^2-4y^2)/(x-2y)+4y^2/(x-2y)=x^2/(x-2y)或者是你的题说的有