(6)编程序,由键盘输入10个整数,输出其中偶数之和以及偶数平均值.

#include"stdio.h"main(){intA,B,C,min;printf("inputA,B,C:");scanf("%d%d%d",&A,&B,&C);min=A;if(min>B){

#includeintmain(){inta,b,c;printf("请输入三个任意整数：\n");scanf("%d%d%d",&a,&b,&c);if(b>a){a=b;if(aa=c;}else

老式写法longint格式用%ld--l是L小写.现在写%d就可以了,longint,shortint,int都用%d程序用ASCII码写成：#includemain(){longs,n,k,i;sc

#includevoidmain()ints,num,i,a;s=0;for(i=1;i

#includeintmain(){\x05inti,a[10],max,min,sum;\x05printf("Pleaseinputtennumbers:\n");\x05scanf("%d",&

给你个最简单的：#include"stdio.h"main(){doublen1,x,t,t1;intcx,i;scanf("%lf,%d",&n1,&cx);t=n1;t1=n1;for(i=1;i

#include#includevoidmain(){intn,i;printf("请输入n:");scanf("%d",&n);intsum=0;for(i=1;i

//这是一版适合自己在数组中自己添加数据的,我初学者,要是显得很冗余的话别笑话我哈,呵呵#includeintmain(void){inta[10];intn;n=1;//像10个元素中录入数据pri

#include<stdio.h>voidmain(){floatnum[10],sum=0,avg;inti;for(i=0;i<10;i++){printf("请输入第

f=2*[1.8,2.2,2.4,2.1,1.9,1.7,1.6,2.0,1.9,1.7,2.6,2.9,2.0,1.9,2.4,2.4,2.3,2.5,2.6,2.3]';A=zeros(4,20)

publicstaticvoidmain(String[]args){Scannersc=newScanner(System.in);System.out.println("请输入：");String

用个循环体,设置循环次数变量i,用于计算输入数的数量,检测推出循环体的字符,如果没有推出命令,继续循环,直到接收到推出命令为止,推出循环后,把输入个数总和除于i,得到平均数输出

用C语言吗再问：是的再答：#includeintmain(){inta=0,sum[4]={0,0,0,0};do{scanf("%d",&a);if(a==1)sum[0]++;if(a==2)su

#includevoidprint(intspace,intnum,inttype){while(space--)putchar('');if(type){while(num--)putch

//if()实现#include<iostream.h>#include<math.h>voidmain(){    doublex,y

#include/*用指针实现：由键盘输入10个整数,将他们按由小到大的顺序排列*/voidmain()/*主函数*/{inti,m,a[10],*p=a,k,j,t;/*定义变量*/printf("

PrivateSubCommand1_Click()Dima(1To20)Fori=1To20a(i)=Val(InputBox("请你输入第"&i&"个数"))NextiPrint"交换前的数为"F

dsolve('DHc=2.21*(Tr-Tc)^1.5*Ac-(7.2+3.84*v)*Ac*(Tc-Ta)+0.037*I*Ac','t')所得结果为1/1000*Ac*(2210*(Tr-Tc)

哥们怎么又是你来?再问：您会不会的啊再答：packagetestt;importjava.util.Scanner;publicclassTest{\x09publicstaticvoidmain(S