(2x^1 2-3y^-1 4)(2x^1 2 3y^-1 4)化简得

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(2x^1 2-3y^-1 4)(2x^1 2 3y^-1 4)化简得
[3x+8y=14 x+5y=12 ] [ 8x-2y=36 3X+y=17 ] [ x+5y=15 5x-y=49 ]

这是一个问题还是分开的啊?再问:feikai再答:/代表几分之几,*代表乘号1.3x+8y=12①14x+5y=12②②-①=11x-3y=011x=3y11/3*x=y再代入①里计得x,再代入②再问

6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5

设x-y=mx+y=n则6m-2n=143m+n=5解得m=2n=-1即x-y=2x+y=-1解得x=1/2y=-3/2

用换元法解方程组 2分之x+y+3分之x-y=6 2(x+y)+(x-y)=12

解析:令x+y=m,x-y=n,那么原方程组可化为:{2分之m+3分之n=6(1){2m+n=12(2)(1)×6可得:3m+2n=36(3)(2)×2可得:4m+2n=24(4)(4)-(3)可得:

已知2x-y/x+3y=2,求代数式4x-2y/x+3y减4x+12y除以2x-y

2x-y/x+3y=2得x+3y/2x-y=1/24x-2y/x+3y减4x+12y除以2x-y=2(2x-y)/x+3y-4(x+3y)/2x-y=2乘以2-4乖以1/2=4-2=2

如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,

x+y+z-6=02x+3y-z-12=02x-y-z=0组成方程组再解x=2y=3z=1

已知2x-y/x+3y=2,求代数式4x-2y/x+3y减4x+12y/2x-y的值

答案是2.4x-2y/x+3y=(2x-y/x+3y)乘以2=4,4x+12y/2x-y=(x+3y/2x-y)乘以4=1/2x4=2,所以代数式等于4-2=2.

先化简,再求值:(x+2y)2-2(x-y)(x+y)+2y(x-3y),其中x=-2,y=12

原式=x2+4xy+4y2-2(x2-y2)+2xy-6y2=x2+4xy+4y2-2x2+2y2+2xy-6y2=-x2+6xy,当x=-2,y=12时,原式=-(-2)2+6×(-2)×12=-4

化简(x+y)-(2x+y/2)-(3x+y/6)-(4x+y/12)-(5x+y/20)-……-(10x+y/90)

(x+y)-(2x+y/2)-(3x+y/6)-(4x+y/12)-(5x+y/20)-……-(10x+y/90)=x-2x-3x-4x-..-10x+y*(1-1/2-1/6-1/12-..1/90

解方程组:(x+3)(y-2)=(x-3)(y+10),(x+1)(y+3)=(x-2)(y+12)

.死算呗xy-2x+3y-6=xy+10x-3y-30,2x-y=4xy+3x+y+3=xy+12x-2y-24,3x-y=92式减1式,x=5,y=6

化简:(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方

(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方=x²-2xy-3y²-x²+4y²-x²+2xy-y²=(x²-

3x/2+5y-12=0 5x-4Y/3+14=0 求X和Y

3x/2+5y-12=0①5x-4y/3+14=0②①×4+②×15得出x=-2,y=3

[(3x+y)(x-y)-(2x+3y)(x-y)]*(x-y)

=(x-y)[(3x+y)-(2x+3y)]*(x-y)=(x-y)*(x-y)(3x+y-2x-3y)=(x-y)(x-y)(x-2y)到底是化简,还是?=(x*x-2xy+y*y)(x-2y)=x

解方程组:x+y/2+x-y/3=6 4(x+y)-5(x-y)=12

设a=x+y,b=x-y原方程组为:a/2+b/3=6,即3a+2b=36,即:12a+8b=1444a-5b=12,即:12a-15b=36相减得:23b=108,得:b=108/23,再得:a=1

【x-3y][x+y]-[x-2y][x +2y]-[x-y

解题思路:根据题意,由整式的运算的知识整理,分析可以求得解题过程:

有这样一道题:"计算(2*x*x*x-3*x*x*y-2*x*y*y)-(x*x*x-2*x*y*y+y*y*y)+【-

解代数式得:-3x的平方y-2y的三次方因为1/2的平方=-1/2的平方,所以结果仍正确给分吧!嘿嘿!

x^3+x-30(分解因式);x^12-y^12;x^15+x^14+x^13.x^2+x+1

x^3+x-30(分解因式)=(x^3-27)+(x-3)=(x-3)(x^2+3x+9)+(x-3)=(x-3)(x^2+3x+9+1)=(x-3)(x^2+3x+10);x^12-y^12;=(x

已知x^2=12,y^2=3,且|x-y|=y-x,求x+y的值.

x^2=12x=±2√3y^2=3y=±√3|x-y|=y-x说明y-x≥0即y≥x所以x不可能等于2√3,即x=-2√3若y=-√3,x+y=-3√3若y=√3,x+y=-√3

化简求值:(x+y)-(2x+1/2y)-(3x+1/6y)-(4x+1/12y)-(5x+1/20y)-.(10x+1

(x+y)-(2x+1/2y)-(3x+1/6y)-(4x+1/12y)-(5x+1/20y)-.-(10x+1/90y)=x+y-2x-1/2y--3x-1/6y-4x-1/12y-5x-1/20y

3y=2x y/3=x/2 12/x=9/y y/x=?y/x=?x/y=?

3y=2x,两边同时乘以1/3x可得y/x=2/3;y/3=x/2,两边同时乘以3/x可得y/x=3/2;12/x=9y,两边都乘以x/9可得x/y=4/3.